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Question

Physics Question on Units and measurement

A wire has a mass (0.3±0.003)g(0.3 \pm 0.003)\, g, radius (0.5±0.005)cm(0.5 \pm 0.005)\,cm and length (6±0.06)cm(6 \pm 0.06) \,cm. The maximum percentage error in the measurement of its density is

A

1%1\%

B

2%2\%

C

3%3\%

D

4%4\%

Answer

4%4\%

Explanation

Solution

Density (ρ)=mπr2l\left(\rho\right)=\frac{m}{\pi r^{2}l} (Δρρ)×100=(Δmm+2×Δrr+Δll)×100\therefore \left(\frac{\Delta\rho}{\rho}\right)\times100=\left(\frac{\Delta m}{m}+2\times\frac{\Delta r}{r}+\frac{\Delta l}{l}\right)\times100 =(0.0030.3+2×0.0050.5+0.066)×100=\left(\frac{0.003}{0.3}+2\times\frac{0.005}{0.5}+\frac{0.06}{6}\right)\times100 =(0.01+0.02+0.01)×100=\left(0.01+0.02+0.01\right)\times100 =4%=4\%