Solveeit Logo

Question

Question: A wire connected in the left gap of a meter bridge balance a\(10 \Omega\) resistance in the right ga...

A wire connected in the left gap of a meter bridge balance a10Ω10 \Omega resistance in the right gap to a point, which divides the bridge wire in the ratio 3 : 2. If the length of the wire is 1 m. The length of one ohm wire is

A

0.057 m

B

0.067 m

C

0.37 m

D

0.134 m

Answer

0.067 m

Explanation

Solution

: Here,

R=32×S=32×10=15Ω\therefore \mathrm { R } = \frac { 3 } { 2 } \times \mathrm { S } = \frac { 3 } { 2 } \times 10 = 15 \Omega

As the length of wire is 1 m.

\thereforelength of one ohm wire = 1/15=0.067 m