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Question

Physics Question on Magnetism and matter

A wire carrying current II and other carrying 2I2I in the same direction produce a magnetic field B at the mid-point. What will be the field when 2I2I wire is switched off?

A

B/2

B

2B

C

B

D

4B

Answer

B

Explanation

Solution

When currents in both the wries are in same direction, then magnetic field at the centre B=B2B1B =B_{2}-B_{1} =μ0(2I)2π(r/2)μ0I2π(r/2)=\frac{\mu_{0}(2 I)}{2 \pi(r / 2)}-\frac{\mu_{0} I}{2 \pi(r / 2)} =μ0Iπr=\frac{\mu_{0} I}{\pi r} When 2I2 I wire is switched off, then magnetic field at the centre B=μ0I2π(r/2)B'=\frac{\mu_{0} I}{2 \pi(r / 2)} =μ0Iπr=B=\frac{\mu_{0} I}{\pi r}=B