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Question: A wire carries a current of \[0.1A\] and has a resistance of \[120{{ }}m\Omega /m\]. What is the pot...

A wire carries a current of 0.1A0.1A and has a resistance of 120mΩ/m120{{ }}m\Omega /m. What is the potential difference across 1m1m of wire?

Explanation

Solution

This question requires the substitution of values in the basic formulae of voltage. Using the values of current and resistance given, we will be able to find the voltage drop across the wire.

Formulae used:
Current: Vd=IR{V_d} = IR
Where RR is the resistances in the circuit and is expressed in Ohms (Ω)(\Omega ), II is the current in the circuit and is expressed in Amperes (A)(A) and Vd{V_d} is the potential difference across the capacitor and is expressed in Coulombs (C)(C).

Complete step by step answer:
It is said in the question that a wire has 0.1A0.1A current flowing in it while a resistance 120mΩ/m120m\Omega /m inhibits the same. We are to determine the potential difference across 1m1m of the same wire. We extract the following data from the question:
R=120mΩ/mR = 120m\Omega /m, I=0.1AI = 0.1A, Length of wire =1m = 1m
Resistance for the given wire is,
R×lengthofwire=120mΩ/m×1m=120mΩR \times length\,of\,wire = 120m\Omega /m\,\, \times \,1m = 120m\Omega
Converting the unit of resistance into SI unit 120×103Ω=0.120Ω120 \times {10^{ - 3}}\Omega = 0.120\Omega
Potential difference is basically the difference between electric potential at two points. Famously it is also directly calculated using Ohm’s Law.

It is observed that the amount of current flowing in the circuit, that is 0.1A0.1A, is quite small. Also, the resistance is also quite inconsequential, 0.12Ω0.12\Omega . Similarly, the potential across the wire due to its internal resistance will be small as well as it is directly proportional to the current and resistance both.
Using Ohm’s Law we get Vd=IR{V_d} = IR.
Substituting the values of resistance (R)(R) and current (I)(I) we get,
Vd=IR=0.1A×0.12Ω=0.012AΩ{V_d} = IR = 0.1A\, \times \,0.12\Omega = 0.012A\,\Omega
But AΩ=VA\,\Omega = V.
Vd=0.012V\therefore{V_d} = 0.012V.

Thus, the potential difference across 1m1m of wire is 0.012V0.012V.

Note: The resistance value in the given question is per meter length of the wire wise. it basically means that the resistance of the entire length of the wire is as such and we need to multiply with it the length of whatever segment of it is provided in the question in order to get that particular segment’s resistance. Potential difference is basically the difference between the voltages at two given points. But it can also be directly calculated using current and resistance values. Potential difference is basically the difference between the voltages at two given points. But it can also be directly calculated using current and resistance values.