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Question: A wire bent in the form of an equilateral triangle ABC of side a carries a current i. Find the magne...

A wire bent in the form of an equilateral triangle ABC of side a carries a current i. Find the magnetic field at a point having equal distance a from A, B and C

A

μ0i2πa\frac{\mu_{0}i}{2\pi a}

B

μ0i23πa\frac{\mu_{0}i}{2\sqrt{3}\pi a}

C

μ0i3πa\frac{\mu_{0}i}{\sqrt{3}\pi a}

D

2μ0i2πa\frac{2\mu_{0}i}{2\pi a}

Answer

μ0i23πa\frac{\mu_{0}i}{2\sqrt{3}\pi a}

Explanation

Solution

Magnetic field due to one side

μ0i23πa\frac{\mu_{0}i}{2\sqrt{3}\pi a}

Resultant magnetic field

B = 3B1 cos (π2φ)\left( \frac{\pi}{2} - \varphi \right)= 3(μ0i23πa)(a233a2)\left( \frac{\mu_{0}i}{2\sqrt{3}\pi a} \right)\left( \frac{\frac{a}{2\sqrt{3}}}{\frac{\sqrt{3}a}{2}} \right) =μ0i23πa\frac{\mu_{0}i}{2\sqrt{3}\pi a}