Solveeit Logo

Question

Question: A whistle whose air column is open at both ends has a fundamental frequency of \(5100\;{\rm{Hz}}\). ...

A whistle whose air column is open at both ends has a fundamental frequency of 5100  Hz5100\;{\rm{Hz}}. If the speed of sound in air is 340  ms1340\;{\rm{m}}{{\rm{s}}^{{\rm{ - 1}}}}, the length of the whistle, in cm is:
A) 53\dfrac{5}{3}
B) 103\dfrac{10}{3}
C) 55
D) 203\dfrac{20}{3}

Explanation

Solution

The speed of sound and length of the whistle is used to determine the value of the fundamental frequency. If we know two values out of three then the third value can be calculated by use of the relation between the speed of air, fundamental frequency, and the length of the whistle.

Complete step by step answer:
Given, the speed of the sound in air is v=340  ms1v = 340\;{\rm{m}}{{\rm{s}}^{{\rm{ - 1}}}}.
The fundamental frequency of a whistle whose air column is open at both ends is f=5100  Hzf = 5100\;{\rm{Hz}}.
Suppose that the length of the whistle that is open at both the end be L.
The fundamental frequency is the ratio of the velocity of sound and two times the length of the pipe. The standard measurement unit for frequency is Hertz.
We know that the fundamental frequency is given by f=v2Lf = \dfrac{v}{{2L}}.
For the length of the whistle, we will reshuffle the above equation in terms of the length of the whistle.
L=v2fL = \dfrac{v}{{2f}}
Here, the length of the pipe is LL, the fundamental frequency is ff and the velocity of the sound in the air is vv.
We will now substitute the known values in the above formula of the fundamental frequency.
L=340  ms12×5100  Hz(1  s11  Hz)\Rightarrow L = \dfrac{{340\;{\rm{m}}{{\rm{s}}^{{\rm{ - 1}}}}}}{{2 \times 5100\;{\rm{Hz}}\left( {\dfrac{{1\;{{\rm{s}}^{ - {\rm{1}}}}}}{{1\;{\rm{Hz}}}}} \right)}}
On simplification,
L=0.0333  m(10  cm1  m)\Rightarrow L = 0.0333\;{\rm{m}}\left( {\dfrac{{10\;{\rm{cm}}}}{{1\;{\rm{m}}}}} \right)
On further simplification,
L=3.33  cm\Rightarrow L = 3.33\;{\rm{cm}}
L=103  cm\Rightarrow L= \dfrac{{{\rm{10}}}}{3}\;{\rm{cm}}

\therefore The length of whistle in cm is calculated to be 103cm\dfrac{10}{3}cm and thus from the given options, only option (B) is correct.

Note:
Make sure to convert the final answer from meter to centimeter otherwise your answer did not match with the given option. Also do not get confused between Hertz and the inverse of second both representing the fundamental frequency and equal in amount.