Question

A wheel with ten metallic spokes each 0.50 m long is rotated with a speed of 120 rev/min in a place normal to the earth's magnetic field at the place. If the magnitude of the field is 0.04 G, the induced emf between the axle and the rim of the wheel is equal to

• A. 1.256 × 10^–3V
• B. 6.28 × 10^–3V
• C. 1.256 × 10^–4V
• D. 6.28 × 10^–6V

Answer 1

Answer: (D)

6.28 × 10^–6V

Answer 2

$e = \frac{1}{2}Bl^{2}\omega = Bl^{2}\pi\nu = (0.04 \times 10^{- 4}) \times (0.5)^{2} \times 3.14 \times \frac{120}{60} = 6.28 \times 10^{- 6}V.$