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Question

Physics Question on Faradays laws of induction

A wheel with 2020 metallic spokes each 1m1\, m long is rotated with a speed of 120rpm120\, rpm in a plane perpendicular to a magnetic field of 0.4G0.4\, G. The induced emf between the axle and rim of the wheel will be, (1G=104T)(1 G = 10^{-4}\, T)

A

2.51×104V2.51 \times 10^{-4}\,V

B

2.51×105V2.51 \times 10^{-5}\, V

C

4.0×105V4.0\times 10^{-5}\, V

D

2.51V2.51 \,V

Answer

2.51×104V2.51 \times 10^{-4}\,V

Explanation

Solution

ε=12Bωr2\varepsilon=\frac{1}{2} B \omega r^{2} ε=12×(0.4×104)×(2π[12060])(1)2\varepsilon=\frac{1}{2}\times\left(0.4\times10^{-4}\right)\times\left(2\pi\left[\frac{120}{60}\right]\right)\left(1\right)^{2} ε=0.8π×104\varepsilon=0.8\pi\times10^{-4} ε=2.512×104\varepsilon=2.512\times10^{-4} Volt