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Question: A wheel of radius 8 units rolls along the diameter of a semicircle of radius 25 units it bumps into ...

A wheel of radius 8 units rolls along the diameter of a semicircle of radius 25 units it bumps into this semicircle. What is the length of the portion of the diameter that cannot be touched by the wheel ?

A

12

B

15

C

17

D

20

Answer

20

Explanation

Solution

AB = Diameter of the bigger circle

= 2(radius) = 2(25) = 50

'C' = Centre of the bigger semicircle.

CQ = 25, PQ = Radius of the smaller circle = 8

CP = CQ – PQ = 25 – 8 = 17

PM = Radius of the smaller circle = 8

CM2 = CP2 – PM2 = 172 – 82

= 289 – 64 = 225 = 152

CM = 15

Similarly, CL = 15.

\ Length of the portion of the diameter of the circle that cannot be touched by the wheel,

AL + MB = AB – (CM + CL)

= 50 – (15 + 15)

= 50 – 30 = 20