Question

A wheel of mass $10\,kg$ has a moment of inertia of $160\,kg-m^2$ about its own axis, the radius of gyration will be

• A. 10 m
• B. 8 m
• C. 6 m
• D. 4 m

Answer 1

Answer: (D)

4 m

Answer 2

Here : Mass of wheel $M=10\, kg$ Moment of inertia $=160\, kg\, m ^{2}$ (where $K$ is radius of gyration) Using relation, $I=M K^{2}$ $160=10 \times K^{2}$ or $K^{2}=16$ or $K=4\, m$