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Question: A wheel has moment of inertia 5×10–3 kg m2 and is making 20 rev/s. The torque needed to stop it in 1...

A wheel has moment of inertia 5×10–3 kg m2 and is making 20 rev/s. The torque needed to stop it in 10 s is ......×10–2 N-m­:

A

2p

B

2.5p

C

4p

D

1.5 p

Answer

2p

Explanation

Solution

α=2π(n2−n1)t=2π(0−20)10=−4πrad/sec⁡2\alpha = \frac{2\pi(n_{2} - n_{1})}{t} = \frac{2\pi(0 - 20)}{10} = - 4\pi rad/\sec^{2}{}

τ=Iα=5×10−3×4π=20π×10−3=2π×10−2N−m\tau = I\alpha = 5 \times 10^{- 3} \times 4\pi = 20\pi \times 10^{- 3} = 2\pi \times 10^{- 2}N - m