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Question

Physics Question on rotational motion

A wheel has angular acceleration of 3.0rad/s23.0 \,rad/s^2 and an initial angular speed of 2.00rad/s2.00 \,rad/s. In a time of 2s2\, s it has rotated through an angle (in radian) of

A

66

B

1010

C

1212

D

44

Answer

1010

Explanation

Solution

Given : angular acceleration α=3.0rad/s2\alpha=3.0\, rad/s^{2} initial angular speed ω0=2.00\omega_{0}=2.00 rad/s time t=2st = 2 \,s θ\theta=? Using, θ=ω0t+12αt2\theta=\omega_{0}t+\frac{1}{2} \alpha t^{2} θ=2×2+12×3×2×2\theta=2\times 2+\frac{1}{2}\times3\times2\times2 =4+6=10=4+6=10 radian