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Question

Physics Question on Current electricity

A Wheatstone bridge has the resistances 10Ω,10Ω,10Ω10\, \Omega,\, 10\, \Omega, 10\, \Omega and 30Ω30\, \Omega in its four arms. What resistance joined in parallel to the 30Ω30\, \Omega resistance will bring it to the balanced condition?

A

2Ω2\, \Omega

B

5Ω5\, \Omega

C

10Ω10\, \Omega

D

15Ω15\, \Omega

Answer

15Ω15\, \Omega

Explanation

Solution

In balanced Wheatstone bridge,
110=1x+130\frac{1}{10}=\frac{1}{x} +\frac{1}{30}
x=15Ωx=15\, \Omega