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Question: A weightless string passes through a slit over a pulley. The slit offers frictional force/to the str...

A weightless string passes through a slit over a pulley. The slit offers frictional force/to the string. The string carries two weights having masses m1and m2where m2>m 1, then acceleration of the weights is

A

(m2m1)gfm1+m2\frac{\left( m_{2} - m_{1} \right)g - f}{m_{1} + m_{2}}

B

f(m2m1)gm1+m2\frac{f - \left( m_{2} - m_{1} \right)g}{m_{1} + m_{2}}

C

(m1+m2)gfm1m2\frac{\left( m_{1} + m_{2} \right)g - f}{m_{1} - m_{2}}

D

m2gf(m1+m2)\frac{m_{2}g - f}{\left( m_{1} + m_{2} \right)}

Answer

(m2m1)gfm1+m2\frac{\left( m_{2} - m_{1} \right)g - f}{m_{1} + m_{2}}

Explanation

Solution

Here m2g – T2 = m2a, …………. (i)

and T1 – m1g = m1a ……….. (ii)

Also (T1 + f) – T2= 0 ……… (iii)

( tension below the slit is T2 and above the slit is T1).

Solving the above equations, a = (m2m1)gfm1+m2\frac{\left( m_{2} - m_{1} \right)g - f}{m_{1} + m_{2}}