Question
Question: A weightless string passes through a slit over a pulley. The slit offers frictional force/to the str...
A weightless string passes through a slit over a pulley. The slit offers frictional force/to the string. The string carries two weights having masses m1and m2where m2>m 1, then acceleration of the weights is

A
m1+m2(m2−m1)g−f
B
m1+m2f−(m2−m1)g
C
m1−m2(m1+m2)g−f
D
(m1+m2)m2g−f
Answer
m1+m2(m2−m1)g−f
Explanation
Solution
Here m2g – T2 = m2a, …………. (i)
and T1 – m1g = m1a ……….. (ii)
Also (T1 + f) – T2= 0 ……… (iii)
( tension below the slit is T2 and above the slit is T1).

Solving the above equations, a = m1+m2(m2−m1)g−f