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Question

Question: A weightless spring which has a force constant oscillates with frequency n when a mass m is suspende...

A weightless spring which has a force constant oscillates with frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from it. The frequency of oscillation will now become

A

nn

B

2n2 n

C

n/2n / \sqrt { 2 }

D

n(2)1/2n ( 2 ) ^ { 1 / 2 }

Answer

nn

Explanation

Solution

n=12πkmn = \frac { 1 } { 2 \pi } \sqrt { \frac { k } { m } }nn=km×mK\frac { n } { n ^ { \prime } } = \sqrt { \frac { k } { m } \times \frac { m ^ { \prime } } { K ^ { \prime } } } n=nn ^ { \prime } = n