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Question: A wedge of mass \(2m\) and a cube of mass m are shown in figure. Between the cube and wedge, there i...

A wedge of mass 2m2m and a cube of mass m are shown in figure. Between the cube and wedge, there is no friction. The minimum coefficient of friction between wedge and ground so that wedge does not move is

(A) 0.100.10
(B) 0.200.20
(C) 0.250.25
(D) 0.500.50

Explanation

Solution

Hint In these kinds of situations the first thing important is to notice the given problem statement. We can observe that this is a question for the straight approach. In this question we will have to simplify the equation to obtain all the known quantities for the final equation.

Complete step by step answer:
Here, first we have to sort out the given quantities:
Mass of the wedge: 2m2m
Mass of the cube:1m1m
And the angle between surface and slope: θ=45o\theta = {45^o}
Now, the equation balancing the forces:
λsinθ=Fr λsinθ=μ(2mg+mgcos2θ) mgsinθcosθ=μ(2mg+mgcos2θ)  \lambda \sin \theta = Fr \\\ \lambda \sin \theta = \mu (2mg + mg{\cos ^2}\theta ) \\\ mg\sin \theta \cos \theta = \mu (2mg + mg{\cos ^2}\theta ) \\\
So, after interpreting the final equation with all know quantities we just have to put the values:
12=μ(2+12) μ=15  \dfrac{1}{2} = \mu (2 + \dfrac{1}{2}) \\\ \mu = \dfrac{1}{5} \\\

Note Most important thing here is to notice the given values, then we can easily interpret the equations. In these types of questions using the correct method is necessary unless it will get twisted.