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Question

Physics Question on Waves

A wave travelling in the +ve+ve xdirectionx-direction having displacement along yy-direction as 1m1m, wavelength 2πm2 \pi m and frequency of 1πHz \frac{1}{\pi} Hz is represented by :

A

y=sin(2πx+2πt) y = \sin (2 \pi x + 2 \pi t)

B

y=sin(x2t) y = \sin (x - 2 t)

C

y=sin(2πx2πt) y = \sin (2 \pi x - 2 \pi t)

D

y=sin(10πx20πt) y = \sin (10 \pi x - 20 \pi t)

Answer

y=sin(x2t) y = \sin (x - 2 t)

Explanation

Solution

y=asin(kxωt)y=a \sin (k x-\omega t)
=sin[2π2πx2π×1πt]=\sin \left[\frac{2 \pi}{2 \pi} x-2 \pi \times \frac{1}{\pi} t\right] =sin(x2t)=\sin (x-2 t)