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Question

Physics Question on Waves

A wave travelling in positive X-direction with a = 0.2 mt., velocity = 360 mt/sec. and λ=60mts,\lambda= 60 \,mts, then correct expression for the wave is:-

A

y=0.2sin[2π(6t+x60)]y=0.2 sin\Bigg[2\pi\Bigg(6t+\frac{x}{60}\Bigg)\Bigg]

B

y=0.2sin[π(6t+x60)]y=0.2 sin\Bigg[\pi\Bigg(6t+\frac{x}{60}\Bigg)\Bigg]

C

y=0.2sin[2π(6tx60)]y=0.2 sin\Bigg[2\pi\Bigg(6t-\frac{x}{60}\Bigg)\Bigg]

D

y=0.2sin[π(6tx60)]y=0.2 sin\Bigg[\pi\Bigg(6t-\frac{x}{60}\Bigg)\Bigg]

Answer

y=0.2sin[2π(6tx60)]y=0.2 sin\Bigg[2\pi\Bigg(6t-\frac{x}{60}\Bigg)\Bigg]

Explanation

Solution

The equation of progressive wave travelling in positive xx-direction is given by
y=asin2πλ(vtx)y=a \sin \frac{2 \pi}{\lambda}(v t-x)
Here a=0.2m,a=0.2 \,m ,
v=360m/sec,v=360\, m / \sec ,
λ=60m\lambda=60\, m
y=0.2sin2π60(360tx)\therefore y=0.2 \sin \frac{2 \pi}{60}(360 \,t-x)
=0.2sin[2π(6tx60)]=0.2 \sin \left[2 \pi\left(6 t-\frac{x}{60}\right)\right]