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Question: A wave travelling along the x-axis is described by the equation \[y\left( {x,t} \right) = 0.005cos\l...

A wave travelling along the x-axis is described by the equation y(x,t)=0.005cos(αxβt)y\left( {x,t} \right) = 0.005cos\left( {\alpha x - \beta t} \right) . If the wavelength and time period of the wave are 0.08m and 2.0s0.08m{\text{ }}and{\text{ }}2.0s respectively, then α and β in appropriate units are:
(A) α=25.00π,β=π\alpha = 25.00\pi ,\beta = \pi
(B) α=0.08π,β=2.0π\alpha = \dfrac{{0.08}}{\pi },\beta = \dfrac{{2.0}}{\pi }
(C) α=0.04π,β=1.0π\alpha = \dfrac{{0.04}}{\pi },\beta = \dfrac{{1.0}}{\pi }
(D) α=12.50π,β=π2.0\alpha = 12.50\pi ,\beta = \dfrac{\pi }{{2.0}}

Explanation

Solution

In order to answer this question, we will write the general equation to mention the variables of the given constant or coefficients. And then in terms of wavelength and time period we will write the formula of αandβ\alpha \,and\,\beta ,a s we already have the value of wavelength and time period.

Complete answer:
The given equation along the x-axis:
y=0.005cos(αxβt)y = 0.005cos\left( {\alpha x - \beta t} \right)
Now, as we know the general equation of the wave travelling along the x-axis:
y=Acos(kxωt)y = A\cos (kx - \omega t)
So, as comparing the given equation and the general equation, we have:
A=0.005mA = 0.005m ,
k=αandω=βk = \alpha \,and\,\omega = \beta
And as we know, αandβ\alpha \,and\,\beta in terms of the wavelength and time period:-
α=2πλ\Rightarrow \alpha = \dfrac{{2\pi }}{\lambda } …….(i)
and, β=2λT \Rightarrow \beta = \dfrac{{2\lambda }}{T} …..(ii)
where, λ\lambda is the wavelength and
TT is the time period of the travelling of waves.
Now, we have already the value of wavelength and time period, i.e.:
λ=0.08m\lambda = 0.08m and,
T=2.0sT = 2.0s
So, we can find the value of αandβ\alpha \,and\,\beta easily:
We will substitute the value of λ\lambda in equation(i)-
α=2πλ=2π0.08=25πm1\therefore \alpha = \dfrac{{2\pi }}{\lambda } = \dfrac{{2\pi }}{{0.08}} = 25\pi {m^{ - 1}} and,
β=2πT=2π2=πrad.s1\therefore \beta = \dfrac{{2\pi }}{T} = \dfrac{{2\pi }}{2} = \pi rad.{s^{ - 1}}
Therefore, the value of αandβ\alpha \,and\,\beta are 25πandπ25\pi \,and\,\pi respectively.

Hence, the correct option is (A) α=25.00π,β=π\alpha = 25.00\pi ,\beta = \pi .

Note:
Progressive wave is a wave that travels continually in the same direction in a medium without changing its amplitude. We shall construct a function that describes the propagation of a wave in a medium and gives the shape of the progressing wave at any point in time throughout its propagation in this section.