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Question

Physics Question on Reflection Of Light By Spherical Mirrors

A wave has velocity uu in medium PP and velocity 2u2u in medium QQ. If the wave is incident in medium PP at an angle 30,30^{\circ}, then the angle of refraction will be

A

3030^{\circ}

B

4545^{\circ}

C

6060^{\circ}

D

9090^{\circ}

Answer

9090^{\circ}

Explanation

Solution

From Snell's law, refractive index (μ)(\mu) is given by
μ=sinisinr...\mu=\frac{\sin i}{\sin r} .. . (i)
where ii is angle of incidence and rr of refraction.
Also, μ=v1v2\mu=\frac{v_{1}}{v_{2}}..(ii)
Equating Eqs. (i) and (ii), we get
μ=sinisinr=v1v2\mu=\frac{\sin i}{\sin r}=\frac{v_{1}}{v_{2}}
sinr=v2v1.sini\Rightarrow \sin r=\frac{v_{2}}{v_{1}} . \sin i
Given, v2=2u,v1=u,i=30,sin30=12v_{2}=2 u, v_{1}=u, i=30^{\circ}, \sin 30^{\circ}=\frac{1}{2}
sinr=2×12=1\therefore \sin r=2 \times \frac{1}{2}=1
r=90\Rightarrow r=90^{\circ}