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Question

Physics Question on Waves

A wave equation which gives the displacement along the direction is given by y=0,001 sin (100r+x)y=0,001\text{ }sin\text{ }(100r+x) where, xx and y are in metre and tt in second. This equation represents a wave

A

travelling with a velocity of 100 m/s in the negative xx- direction

B

travelling with a velocity of 50π\frac{50}{\pi } m/s in the positive xx- direction

C

of wavelength 1 m

D

of frequency 100π\frac{100}{\pi } Hz

Answer

travelling with a velocity of 100 m/s in the negative xx- direction

Explanation

Solution

The standard equation of a wave, travelling with amplitude a in the negative xx- direction with angular velocity ω\omega is given by y=asin(ωt+kx)y=a\sin (\omega t+kx) ...(i) where, kk is wave number. Given equation of wave is y=0.001sin(100t+x)y=0.001\,\sin (100t+x) ..(ii) Comparing Eqs. (i) and (ii), we get v=ωk=1001v=\frac{\omega }{k}=\frac{100}{1} =100m/s=100\,m/s