Question
Question: A wave equation is represented as \( r=A\sin \alpha \dfrac{\left( x-y \right)}{2}\cos \omega t+\alph...
A wave equation is represented as r=Asinα2(x−y)cosωt+α2(x+y) , where x and y are in meters and t is in seconds . Which of the following options is correct?
(A)The wave is a stationary wave
(B)The wave is a progressive wave propagating along positive x - axis
(C)The wave is progressive propagating at right angles to the positive x-axis
(D)All point lying on line y=x+α4π are always at rest
Solution
Hint : In order to solve this question, first of all we must determine the nature of the given wave, whether it is a standing wave or a progressive wave , that can be determined by comparing the given equation to the general equation for standing and the progressive waves.
General Equation for standing wave: y=2Asinωtcoskx
General Equation for progressive wave: y=Asin(ωt−kx)
sin(2n+1)π=0
v=dtdr
Where, v is velocity.
Complete Step By Step Answer:
Firstly, the given wave equation is:
r=Asinα2(x−y)cosωt+α2(x+y)
The general equations for the standing and the progressive waves are:
For standing wave: y=2Asinωtcoskx
For progressive wave: y=Asin(ωt−kx)
Since the given wave equation does not match with any of the above equations, it is neither a standing nor a progressive wave
Replace y by y=x+α4π
r=Asinα2x−x−α4πcosωt−α2x+x+α4π⇒r=Asin(−2π)cos(ωt−αx−2π)⇒r=0
And finding the velocity, we get
dtdr=0⇒v=0
Therefore, we can say that all points lying at the line with the equation y=x+α4π are always at rest because the velocity is zero.
Therefore, option (D) is correct.
Note :
According to the wave equation, this wave is neither a standing nor a progressive wave . This rules out the first three options and then y is replaced by y=x+α4π to get a result matching with fourth. But to rule out other options is equally important.