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Question

Physics Question on mechanical properties of fluid

A water tank standing on the floor has two small holes vertically one above the other punched on one side. The holes are h1h_1 cm and h2h_2 cm above the floor. How high does water stand in the tank when the jets from the holes hit the floor at the same point ?

A

(h2h1)(h_2-h_1)

B

h2+h1h_2+h_1

C

(h22h12)(h_2\,^2-h_1\,^2)

D

h2h2h1\frac{h_2}{h_2-h_1}

Answer

h2+h1h_2+h_1

Explanation

Solution

R1=R2R_1 = R_2 \Rightarrow 2g(Hh1)2h1g=2g(Hh2)2h2g\sqrt{2g(H - h_1)} \sqrt{\frac{2h_1}{g}} = \sqrt{2g (H - h_2)} \sqrt{\frac{2h_2}{g}}