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Question: A water is being poured at the rate of 36 into a cylindrical vessel whose circular base is of radius...

A water is being poured at the rate of 36 into a cylindrical vessel whose circular base is of radius 3m then the water level in cylindrial is rising at the rate of

A

4π4\pi

B

4π\frac{4}{\pi}

C

14π\frac{1}{4\pi}

D

π4\frac{\pi}{4}

Answer

4π\frac{4}{\pi}

Explanation

Solution

The volume of water in a cylindrical vessel is given by

V=πr2h.V=\pi r^2 h.

For a cylinder with radius r=3r=3 m,

V=9πh.V=9\pi h.

Differentiating both sides with respect to time tt, we get

dVdt=9πdhdt.\frac{dV}{dt} = 9\pi \frac{dh}{dt}.

Given dVdt=36\frac{dV}{dt} = 36, solving for dhdt\frac{dh}{dt} gives

dhdt=369π=4π.\frac{dh}{dt} = \frac{36}{9\pi} = \frac{4}{\pi}.