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Question

Physics Question on Uniform Circular Motion

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is vv, the total area around the fountain that gets wet is

A

πv2g2\pi \frac{v^{2}}{g^{2}}

B

πv2g\pi \frac{v^{2}}{g}

C

πv4g2\pi \frac{v^{4}}{g^{2}}

D

π2v4g2\frac{\pi}{2} \frac{v^{4}}{g^{2}}

Answer

πv4g2\pi \frac{v^{4}}{g^{2}}

Explanation

Solution

Area =πRmax2=\pi R_{\max }^{2} Rmax=v2sin90g=v2gR_{\max }=\frac{v^{2} \sin 90^{\circ}}{g}=\frac{v^{2}}{g} \Rightarrow Area =πv4g2=\frac{\pi v^{4}}{g^{2}}