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Question: A wall is moving with velocity u and a source of sound moves with velocity u/2 in the same direction...

A wall is moving with velocity u and a source of sound moves with velocity u/2 in the same direction as shown in the figure. Assuming that the sound travels with velocity 10u. The ratio of incident sound wavelength on the wall to the reflected sound wavelength by the wall, is equal to –

A

9 : 11

B

11 : 9

C

4 : 5

D

5 : 4

Answer

9 : 11

Explanation

Solution

li = wavelength of the incident sound

= 10uu2f=19u2f\frac{10u - \frac{u}{2}}{f} = \frac{19u}{2f}

fi = frequency of the incident sound

= 10uu10uu2\frac{10u - u}{10u - \frac{u}{2}}f =1819\frac{18}{19}f = f = fr = frequency of the reflected sound

lr = wavelength of the reflected sound = 10u+ufr\frac{10u + u}{f_{r}} = × 19 = 11×1918\frac { 11 \times 19 } { 18 } . uf\frac { \mathrm { u } } { \mathrm { f } }

λiλr\frac { \lambda _ { i } } { \lambda _ { r } } = × 18f11×19u\frac { 18 \mathrm { f } } { 11 \times 19 \mathrm { u } } = 911\frac { 9 } { 11 }