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Question: A volume V of a gas at a temperature \[{T_1}\] ​, and a pressure p is enclosed in a sphere. It is co...

A volume V of a gas at a temperature T1{T_1} ​, and a pressure p is enclosed in a sphere. It is connected to another sphere of volume V2\dfrac{V}{2} by a tube and stopcock. The second sphere is initially evacuated and the stopcock is closed. If the stopcock is opened the temperature of the gas in the second sphere becomes T2{T_2} . The first sphere is maintained at a temperature T1{T_1} ​. What is the final pressure p1{p_1} ​within the apparatus?

Explanation

Solution

If we take total number of molecules of the gas be n. of which n1{n_1} are in the larger sphere and n2{n_2} in the smaller sphere after the stopcock is opened and Using ideal gas equation, PV=nRTPV = nRT . Total moles of gas (n) in first sphere will be P1VRT1\dfrac{{{P_1}V}}{{R{T_1}}} and moles in the second sphere will be P1V2RT2\dfrac{{{P_1}V}}{{2R{T_2}}} . Hence, we can find the final pressure p1{p_1}within the apparatus.

Complete step by step answer:
Let the total number of molecules of the gas be n. of which n1{n_1} are in the larger sphere and n2{n_2} in the smaller sphere after the stopcock is opened.
Using ideal gas equation,
PV=nRTPV = nRT
n=PVRTn = \dfrac{{PV}}{{RT}}
Case I - When the stopcock is closed
Pressure enclosed in sphere =p = p
Temperature of sphere =T1 = {T_1}
Volume =V = V
Therefore, total moles of gas
(n)=PVRT1(n) = \dfrac{{PV}}{{R{T_1}}}
Case II - When the stopcock is opened.
Pressure within the apparatus, i.e., final pressure =p1 = {p_1}
Temperature of first sphere =T1 = {T_1}
Temperature of second sphere =T2 = {T_2}
Volume of first sphere =V = V
Volume of second sphere =V2 = \dfrac{V}{2}
Therefore, Moles of gas in first sphere n1=p1VRT1{n_1} = \dfrac{{{p_1}V}}{{R{T_1}}}
and Moles of gas in second sphere
n2=p1(V2)RT2\Rightarrow {n_2} = \dfrac{{{p_1}\left( {\dfrac{V}{2}} \right)}}{{R{T_2}}}
n2=p1V2RT2\Rightarrow {n_2} = \dfrac{{{p_1}V}}{{2R{T_2}}}
Now,
Total moles of gas = moles of gas in first sphere + moles of gas in second sphere
n=n1+n2n = {n_1} + {n_2}
pVRT1=p1VRT1+p1V2RT2\Rightarrow \dfrac{{pV}}{{R{T_1}}} = \dfrac{{{p_1}V}}{{R{T_1}}} + \dfrac{{{p_1}V}}{{2R{T_2}}}
p1=2pT22T2+T1\Rightarrow {p_1} = \dfrac{{2p{T_2}}}{{2{T_2} + {T_1}}}

Note: We can define an ideal gas as a hypothetical gaseous substance whose behaviour is independent of attractive and repulsive forces and can be completely described by the ideal gas law.