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Question: A volatile organic compound weighing \[0.2\;g\], on heating in Victor Meyer's tube, displaced \[30\;...

A volatile organic compound weighing 0.2  g0.2\;g, on heating in Victor Meyer's tube, displaced 30  mL30\;mL of air at 270C{27^0}C and 756  mm756\;mm atmospheric pressure. Determine the molecular mass of the compound (Aqueous tension at270C=26  mm270C = 26\;mm).
A.180.2
B.200.5
C.199.1
D.190.6

Explanation

Solution

In order to calculate the molecular mass of the compound the formula used isMass of the compoundVolume of vapors at NTP(in mL)×22400\dfrac{{Mass{\text{ }}of{\text{ }}the{\text{ }}compound}}{{Volume{\text{ }}of{\text{ }}vapors{\text{ }}at{\text{ }}NTP(in{\text{ }}mL)}} \times 22400, the mass of the compound is the given mass, and NTP is normal temperature and pressure condition.

Complete step by step answer:
According to the question;
The weight of volatile organic compound is = 0.2g0.2g
Volume of displaced air = 30ml30ml
Temperature = 27C{27^ \circ }C
Converting temperature to kelvin from Celsius scale;
Temperature =27C=(27+273)K=300K{27^ \circ }C = \left( {27 + 273} \right)K = 300K
According to the question, aqueous tension at 27C{27^ \circ }C is 26mm26mm
Pressure = (756  26) mm Hg\left( {756{\text{ }} - {\text{ }}26} \right){\text{ }}mm{\text{ }}Hg
Pressure = 730 mm Hg730{\text{ }}mm{\text{ }}Hg
So, the volume of displaced air at NTP will be given =730mmHg×30mL300K×273K760mmHg = \dfrac{{730mm\:Hg \times 30mL}}{{300K}} \times \dfrac{{273K}}{{760mmHg}}
Volume of the air at NTP = 22.5 mL22.5{\text{ }}mL
To find the molecular mass the formula used will be;
Mass = Mass of the compoundVolume of vapors at NTP(in mL)×22400\dfrac{{Mass{\text{ }}of{\text{ }}the{\text{ }}compound}}{{Volume{\text{ }}of{\text{ }}vapors{\text{ }}at{\text{ }}NTP(in{\text{ }}mL)}} \times 22400
By substituting the value in this formula now, the molecular mass will be;
Molecular Mass =0.2×2240022.5=199.1\dfrac{{0.2 \times 22400}}{{22.5}} = 199.1
Molecular Mass= 199.1199.1
Thus the correct option is C.

Additional information : Molecular mass is the sum total of the weight of its combining constituent. If we want to calculate the molecular mass of a simple compound say C2H5{C_2}{H_5} then, the steps followed will be;
A.Carbon= Mass of carbon x number of carbon = 2×122 \times 12
Carbon = 2424
B.Hydrogen = mass of hydrogen x number of hydrogen
Hydrogen = 1×51 \times 5
Hydrogen = 55
So the molecular mass for C2H5{C_2}{H_5} will be =24+5=2924 + 5 = 29

Note:
The molecular mass formula is used to calculate the mass of the compound formed from the mass combination of its constituents.
-The temperature given unit is converted to SI unit kelvin to make the calculations easy.
-Victor Meyer’s method is used to calculate the vapour density, in which the sample is heated in a tube and its vapours are collected and their density is calculated.