Question

A violet compound of manganese (P) decomposes on heating to liberate oxygen and compound (Q) and (R) of manganese are formed. Compound (R) reacts with KOH in the presence of potassium nitrate to given compound (Q). on heating compound (R) with conc. $H_{2}SO_{4}$ and NaCl, chlorine gas is liberated and a compound (S) of manganese along with other products is formed compounds P to S are

P Q R S

• A. $KMnO_{4}$ $K_{2}MnO_{4}$ $MnCl_{2}$ $MnO_{2}$
• B. $K_{2}MnO_{4}$ $MnO_{2}$ $KMnO_{4}$ $MnCl_{2}$
• C. $KMnO_{4}$ $K_{2}MnO_{4}$ $MnO_{2}$ $MnCl_{2}$
• D. $K_{2}MnO_{4}$ $KMnO_{4}$ $MnO_{2}$ $MnCl_{2}$

Answer 1

Answer: (C)

$KMnO_{4}$ $K_{2}MnO_{4}$ $MnO_{2}$ $MnCl_{2}$

Answer 2

$\mathrm { P } = \mathrm { KMnO } _ { 4 } , \mathrm { Q } = \mathrm { K } _ { 2 } \mathrm { MnO } _ { 4 } , \mathrm { R } = \mathrm { MnO } _ { 2 } , \mathrm {~S} = \mathrm { MnCl } _ { 2 }$ $\underset{(P)}{2KMnO_{4}}\overset{\quad\Delta\quad}{\rightarrow}\underset{(Q)}{K_{2}MnO_{4}} + \underset{(R)}{MnO_{2}} + O_{2}$

$2MnO_{2} + 4KOH + O_{2} \rightarrow 2K_{2}MnO_{4} + 2H_{2}O$

}{ + 2H_{2}O + Cl_{2}}$$