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Question: A vessel is filled with an ideal gas at a pressure of 10 atmospheres and temperature 27C. Half of th...

A vessel is filled with an ideal gas at a pressure of 10 atmospheres and temperature 27C. Half of the mass of the gas is removed from the vessel and temperature of the remaining gas is increased to 87C. Then the pressure of the gas in the vessel will be

A

5 atm

B

6 atm

C

7 atm

D

8 atm

Answer

6 atm

Explanation

Solution

PV=mrT=PmTPV = mrT = P \propto mT Ž P1P2=m1m2×T1T2\frac{P_{1}}{P_{2}} = \frac{m_{1}}{m_{2}} \times \frac{T_{1}}{T_{2}}

Ž 10P2=mm/2×(273+27)(273+87)\frac{10}{P_{2}} = \frac{m}{m/2} \times \frac{(273 + 27)}{(273 + 87)} Ž P2=6atmP_{2} = 6atm