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Question: A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on ...

A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is :

A

1.8 atm

B

3 atm

C

0.3 atm

D

0.18

Answer

1.8 atm

Explanation

Solution

CO2(g) + C(s) 2CO (g)

0.5 atm 0.5–p 2p

Total pressure = 0.5 – P + 2P = 0.8

P = 0.3

KpPCO2PCO2=(2P)2(0.5P)=(0.6)2(0.50.3)K_{p}\frac{P_{CO}^{2}}{P_{CO_{2}}} = \frac{(2P)^{2}}{(0.5 - P)} = \frac{(0.6)^{2}}{(0.5 - 0.3)}

Kp = 1.8