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Question

Physics Question on Moving charges and magnetism

A Very long magnef of pole strength 4 Am is placed vertically with its one pole on the tabIe .The distance from the pole, the neutral point will be formed is (BH=4×105T)(B_H=4 \times 10^{-5}T)

A

0.5 m

B

0.1 m

C

0.15 m

D

6.66 m

Answer

0.1 m

Explanation

Solution

μ04πmd2=BH\frac{\mu_0}{4\pi} \frac{m}{d^2} = B_H