Question

A vertical tube of length 100 cm contains a mercury pallet of length 5 cm as shown in figure. The length of tube above mercury pallet if the tube is inverted is nearly : (atm pressure = 75 cm)

• A. 45 cm
• B. 57 cm
• C. 60 cm
• D. 62 cm

Answer 1

Answer: (B)

57 cm

Answer 2

P₁ × 50 = P₂ × x Ž x = $\frac{50P_{1}}{P_{2}}$

P₁ = 80 cm of Hg

P₂ = 70 cm of Hg

\ x = $\frac{50 \times 80}{70}$

= 57.12 cm » 57 cm