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Question: A vertical pole stands at a point O on a horizontal ground. A and B are points on the ground \( 10m ...

A vertical pole stands at a point O on a horizontal ground. A and B are points on the ground 10m10m apart. The pole subtends an angle 300{30^0} and 600{60^0} at A and B respectively. Then the height of the tower equals.
(A) 103  m10\sqrt 3\;m
(B) 53  m5\sqrt 3\;m
(C) 153  m15\sqrt 3\;m
(D) None of these

Explanation

Solution

Hint : Use the triangle property of tanθ\tan \theta to calculate the unknown variables using the given conditions. To solve this question, we will assume that the pole stands vertically upward on the ground making angle 900{90^0} with the ground.

Complete step-by-step answer :
Observe that diagram

It is given in the question that,
PAO=300\angle PAO = {30^0}
PBO=600\angle PBO = {60^0}
AB=10mAB = 10 m
We have to find the height of the tower.
Let us assume that the height of the tower be hh
Let us consider the ΔPAO\Delta PAO
In ΔPAO\Delta PAO
Using the triangle properties of trigonometric function, we can write
tanPAO=hOA\tan \angle PAO = \dfrac{h}{{OA}}
tan300=hOA\Rightarrow \tan {30^0} = \dfrac{h}{{OA}}
From the figure, we can observe that
OA=AB+BOOA = AB + BO
OA=10+BO\Rightarrow OA = 10 + BO
Therefore, we get
tan300=h10+BO\tan {30^0} = \dfrac{h}{{10 + BO}}
By substituting the value of tan300=13\tan {30^0} = \dfrac{1}{{\sqrt 3 }} in above equation, we can write
13=h10+BO\dfrac{1}{{\sqrt 3 }} = \dfrac{h}{{10 + BO}}
By cross multiplying the above equation, we get
10+BO=h310 + BO = h\sqrt 3
BO=h310\Rightarrow BO = h\sqrt 3 - 10
Now let us consider the triangle ΔPBO\Delta PBO
In ΔPBO\Delta PBO
Using the triangle properties of trigonometric function, we can write
tanPBO=hOB\tan \angle PBO = \dfrac{h}{{OB}}
tan600=hOB\Rightarrow \tan {60^0} = \dfrac{h}{{OB}}
By substituting the value of tan600=3\tan {60^0} = \sqrt 3 and the value of OB=h310OB = h\sqrt 3 - 10 calculated above, we can write
3=hh310\sqrt 3 = \dfrac{h}{{h\sqrt 3 - 10}}
By cross multiplying, we get
3(h310)=h\sqrt 3 (h\sqrt 3 - 10) = h
By simplifying it, we get
3h103=h3h - 10\sqrt 3 = h
2h=103\Rightarrow 2h = 10\sqrt 3
Dividing both the sides by 22 we get
h=53h = 5\sqrt 3
So, the height of the tower is 53  m5\sqrt 3\; m
Therefore, form the above explanation, the correct answer is, option (B) 53  m5\sqrt 3\;m
So, the correct answer is “Option B”.

Note : To use the triangle properties of a trigonometric function, we need to have a right angled triangle. Therefore, we cannot question the above if we do not consider the pole to be perpendicular to the ground. We have given two conditions to solve. In such a case, we use one condition to find one variable and the substitute that variable into the second condition to get the final answer. Just like we did in the above question by finding the value of BO using the first condition and the substituting that value into the second condition to find the height of the tower.