Question

A verniercalliper with vernier constant equal to .02 cm is to be designed. If 1 MSD = 0.1 cm. Then total number of vernier scales should be –

• A. 10
• B. 20
• C. 5
• D. 200

Answer 1

Answer: (C)

5

Answer 2

LC = $\frac { \mathrm { MSD } } { \mathrm { n } }$

\ n = $\frac { \mathrm { MSD } } { \mathrm { LC } }$ = $\frac { 0.1 } { .02 }$ = 5