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Question

Physics Question on Motion in a straight line

A vehicle travels half the distance LL with speed v1v_1 and the other half with speed v2v_2 , then its average speed is

A

v1+v22\frac{v_{1}+v_{2}}{2}

B

2v1+v2v1+v2\frac{2v_{1}+v_{2}}{v_{1}+v_{2}}

C

2v1v2v1+v2\frac{2v_{1}v_{2}}{v_{1}+v_{2}}

D

L(v1+v2)v1v2\frac{L\left(v_{1}+v_{2}\right)}{v_{1}v_{2}}

Answer

2v1v2v1+v2\frac{2v_{1}v_{2}}{v_{1}+v_{2}}

Explanation

Solution

Time taken to travel first half distance, t1=L/2v1=L2v1t_{1}=\frac{L/2}{v_{1}}=\frac{L}{2v_{1}} Time taken to travel second half distance, t2=L/2v2=L2v2t_{2}=\frac{L/2}{v_{2}}=\frac{L}{2v_{2}} Total time taken =t1+t2=L2v1+L2v2=t_{1}+t_{2}=\frac{L}{2v_{1}}+\frac{L}{2v_{2}} Average speed =Total distance travelledTotal time taken=\frac{\text{Total distance travelled}}{\text{Total time taken}} =LL2v1+L2v2=112[1v1+1v2]=\frac{L}{\frac{L}{2v_{1}}+\frac{L}{2v_{2}}}=\frac{1}{\frac{1}{2}\left[\frac{1}{v_{1}}+\frac{1}{v_{2}}\right]} =2v1v2v2+v1=\frac{2v_{1}v_{2}}{v_{2}+v_{1}}