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Question

Question: A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of fric...

A vehicle of mass m is moving on a rough horizontal road with momentum P. If the coefficient of friction between the tyres and the road be μ, then the stopping distance is

A

P2μmg\frac { P } { 2 \mu m g }

B

P22μmg\frac { P ^ { 2 } } { 2 \mu m g }

C

P2μm2g\frac { P } { 2 \mu m ^ { 2 } g }

D

P22μm2g\frac { P ^ { 2 } } { 2 \mu m ^ { 2 } g }

Answer

P22μm2g\frac { P ^ { 2 } } { 2 \mu m ^ { 2 } g }

Explanation

Solution

S=u22μg=m2u22μgm2=P22μm2gS = \frac { u ^ { 2 } } { 2 \mu g } = \frac { m ^ { 2 } u ^ { 2 } } { 2 \mu g m ^ { 2 } } = \frac { P ^ { 2 } } { 2 \mu m ^ { 2 } g }