Question

A vehicle of 100 kg is moving with a velocity of 5 m/sec. To stop it in $\frac{1}{10}$sec, the required force in opposite direction is

• A. 5000 N
• B. 500 N
• C. 50 N
• D. 1000 N

Answer 1

Answer: (A)

5000 N

Answer 2

$m = 100kg$ $u = 5m/s,$ $v = 0$ t = 0.1 sec

$Force = \frac{mdv}{dt} = \frac{m(v - u)}{t}$ $= \frac{100(0 - 5)}{0.1}$

$F = - 5000N$