Question

A vehicle is moving with a velocity $v$ on a curved road of width $b$ and radius of curvature $R$. For counteracting the centrifugal force on the vehicle, the difference in elevation required in between the outer and inner edges of the road is

• A. $\frac{v^{2}b}{Rg}$
• B. $\frac{rb}{Rg}$
• C. $\frac{vb^{2}}{Rg}$
• D. $\frac{vb}{R^{2}g}$

Answer 1

Answer: (A)

$\frac{v^{2}b}{Rg}$

Answer 2

For Banking of road $\tan\theta = \frac{v^{2}}{rg}$and $\tan\theta = \frac{h}{l}$

$\therefore\frac{v^{2}}{rg} = \frac{h}{l}$ ⇒ $h = \frac{v^{2}l}{rg} = \frac{v^{2}b}{Rg}$ [As $l = b$and $r = R$ given]