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Question: A unit vector perpendicular to the direction of ![](https://cdn.pureessence.tech/canvas_13.png?top_l...

A unit vector perpendicular to the direction of is

A

B

C

D

Answer

Explanation

Solution

Unit vector perpendicular to the directions of and is

∣A→×B→∣=(−14)2+(−7)2+(−7)2=76| \overrightarrow { \mathrm { A } } \times \overrightarrow { \mathrm { B } } | = \sqrt { ( - 14 ) ^ { 2 } + ( - 7 ) ^ { 2 } + ( - 7 ) ^ { 2 } } = 7 \sqrt { 6 }

∴n^=−14i^−7j^−7k^76=−2i^−j^−k^6\therefore \hat { \mathrm { n } } = \frac { - 14 \hat { \mathrm { i } } - 7 \hat { \mathrm { j } } - 7 \hat { \mathrm { k } } } { 7 \sqrt { 6 } } = \frac { - 2 \hat { \mathrm { i } } - \hat { \mathrm { j } } - \hat { \mathrm { k } } } { \sqrt { 6 } }