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Question

Physics Question on Current electricity

A uniform wire of resistance RR, of the radius rr is uniformly drawn until its radius is reduced to r/nr/ n, Its new resistance is

A

nRn R

B

n3Rn^3 R

C

n2Rn^2 R

D

n4Rn^4 R

Answer

n4Rn^4 R

Explanation

Solution

Here, R=ρlA=ρlπr2R = \frac{\rho l}{A} = \frac{\rho l}{\pi r^2}
As, r=rn,l=?r' = \frac{r}{n} , l' = ?
or, r2l=(rn)2lr^2 l = \left( \frac{r}{n} \right)^2 l'
or, l=n2ll' = n^2 l
New resistance of the wire, R=ρlA=ρlπr2R' = \frac{\rho l'}{A'} = \frac{ \rho l'}{\pi r'^2}
or , R=ρπ×n2l(r/n)2=n4ρlπr2=n4RR' = \frac{\rho}{\pi} \times \frac{n^2 l }{( r / n)^2} = n^4 \frac{\rho l}{\pi r^2} = n^4 R