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Question

Physics Question on Waves

A uniform wire of length LL, diameter DD and density PP is stretched under a tension TT. The correct relation between its fundamental frequency f'f' , the length LL and the diameter DD is ............

A

fLD2f\propto\frac{L}{D^2}

B

f1LD2f\propto\frac{1}{L D^2}

C

f1LDf\propto\frac{1}{LD}

D

f1LDf\propto\frac{1}{L\sqrt{D}}

Answer

f1LDf\propto\frac{1}{LD}

Explanation

Solution

The fundamental frequency is
f=12LTμf=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}
f=12LTρπD24=1LDTπρf=\frac{1}{2 L} \sqrt{\frac{T}{\rho \pi \frac{D^{2}}{4}}}=\frac{1}{L D} \sqrt{\frac{T}{\pi \rho}}
f1LD\therefore f \propto \frac{1}{L D}