Solveeit Logo

Question

Physics Question on Current electricity

A uniform wire of length ll and radius rr has a resistance of 100Ω100 \, \Omega . It is recast into a wire of radius r2\frac{r}{2}. The resistance of new wire will be :

A

1600Ω1600 \, \Omega

B

400Ω400 \, \Omega

C

200Ω200 \, \Omega

D

100Ω100 \, \Omega

Answer

1600Ω1600 \, \Omega

Explanation

Solution

R=ρlAAl=VR=\frac{\rho l}{A} \,\,\,\,\,A l=V
R=ρvA2R=\frac{\rho v}{A^{2}}
ρ\rho \rightarrow constant
vv \rightarrow constant
R1A21r2R \propto \frac{1}{A^{2}} \propto \frac{1}{r^{2}}
R1r4R \propto \frac{1}{r^{4}}
R2=16R1=1600ΩR_{2}=16 \,R_{1}=1600 \,\Omega