Solveeit Logo

Question

Physics Question on laws of motion

A uniform sphere of weight WW and radius 5cm5\, cm is being held by a string as shown in the figure. The tension in the string will be :

A

12W512 \frac{W}{5}

B

5W125 \frac{W}{12}

C

13W513 \frac{W}{5}

D

13W1213 \frac{W}{12}

Answer

13W1213 \frac{W}{12}

Explanation

Solution

PQ=OP2+OQ2PQ = \sqrt{OP^{2}+OQ^{2}}
=132+52=12= \sqrt{13^{2}+5^{2}} = 12
Tension in the string TT, so, Tcosθ=wTcos\theta = w
T=wcosθ=1312W\Rightarrow T = \frac{w}{cos\theta} = \frac{13}{12}W