Question
Physics Question on System of Particles & Rotational Motion
A uniform solid cylindrical roller of mass 'm' is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is 'a' and it is rolling without slipping then the value of 'F' is :
A
ma
B
2ma
C
23 ma
D
25 ma
Answer
23 ma
Explanation
Solution
F−f=ma...(1)
fr=(2mr2)(ra)...(2)
f=2ma. Therefore, F=23ma