A uniform rope of mass (M) and length / hangs from a ceiling... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A uniform rope of mass $M$ and length / hangs from a ceiling. A transverse pulse at a height $x$ above the lower end of the rope will move with speed $c$ is

A

$\sqrt{gx}$

B

$\sqrt{Mgx}$

C

$\sqrt{Mgl/x}$

D

$\sqrt{M/x}$

Answer

$\sqrt{gx}$

Explanation

Solution

$c = \sqrt{\frac{T}{\mu}}$ . Here T = $\left(\frac{M}{l}x \right) g$ and $\mu = \frac{M}{l}$ , Hence $c = \sqrt{gx}$