Question
Physics Question on laws of motion
A uniform rope of length L, resting on a frictionless horizontal surface, is pulled at one end by a force F. The tension in the rope at a distance I from this end is
A
F
B
LlF
C
lLF
D
(1−Ll)F
Answer
(1−Ll)F
Explanation
Solution
Mass of length l=mL, where m is mass per unit length of the rope. From Newton's 2 nd law, Force = mass × acceleration F=mLa ⇒a=mLF Tension in rope at distance l from the given end T=m(L−l)a =m(L−l)mLF T=(1−Ll)F