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Question: A uniform rod of mass M<sub>1</sub> is hinged at its upper end. A particle of mass M<sub>2</sub> mov...

A uniform rod of mass M1 is hinged at its upper end. A particle of mass M2 moving horizontally strikes the rod at its mid point elastically. If the particle comes to rest after collision, the value of M1M2\frac{M_{1}}{M_{2}} is –

A

34\frac{3}{4}

B

43\frac{4}{3}

C

23\frac{2}{3}

D

32\frac{3}{2}

Answer

34\frac{3}{4}

Explanation

Solution

LH = M2v L2\frac{L}{2} = M1L23\frac{M_{1}L^{2}}{3} w

w = 3M2v2M1L\frac{3M_{2}v}{2M_{1}L} …(1)

for e = 1, vCM = v = ωL2\frac{\omega L}{2} …(2)

Ž 2vL\frac{2v}{L} = 3M2v2M1L\frac{3M_{2}v}{2M_{1}L}

Ž M1M2\frac{M_{1}}{M_{2}} = 34\frac{3}{4}