Question

A uniform rod of mass $m$ and length $l_0$ is pivoted at one end and is hanging in the vertical direction. The period of small angular oscillations of the rod is

• A. $T=3\pi \sqrt {\frac {2l_0}{3g}}$
• B. $T=4\pi \sqrt {\frac {l_0}{3g}}$
• C. $T=4\pi \sqrt {\frac {2l_0}{3g}}$
• D. $T=2\pi \sqrt {\frac {2l_0}{3g}}$

Answer 1

Answer: (D)

$T=2\pi \sqrt {\frac {2l_0}{3g}}$

Answer 2

The correct option is (D): $T=2\pi \sqrt {\frac {2l_0}{3g}}$.