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Question

Physics Question on Electric Field

A uniform rod of length \ell and mass mm is free to rotate in a vertical plane about AA. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about AA is m23\frac{m \ell^{2}}{3} ):

A

3g2\frac{3 g}{2 \ell}

B

23g\frac{2 \ell}{3 g }

C

3g22\frac{3 g }{2 \ell^{2}}

D

mg2mg \frac{\ell}{2}

Answer

3g2\frac{3 g}{2 \ell}

Explanation

Solution